The flight distance between the nearest airports Rancho-Cucamonga (ONT) and Norwalk (DXR) is 2,437.49 mi (3,922.77 km). This corresponds to an approximate flight time of 5h 6min. Similar flight routes: ONT → DXR , ONT → BDR , ONT → DXR , ONT → DXR , ONT → BDRBearing: 65.29° (ENE)
The initial bearing on the course from Rancho-Cucamonga to Norwalk is 65.29° and the compass direction is ENE.Midpoint: 39.73793,-96.59803
The geographic midpoint between Rancho-Cucamonga and Norwalk is in 1,220.18 mi (1,963.70 km) distance between both points in a bearing of 65.29°. It is located in United States of America, Kansas, Marshall County.Distance: 2,440.37 mi (3,927.39 km)
The shortest distance (air line) between Rancho-Cucamonga and Norwalk is 2,440.37 mi (3,927.39 km).Driving route: -- ( - )
The shortest route between Rancho-Cucamonga and Norwalk is according to the route planner. The driving time is approx. . Half of the trip is reached in .Time difference: 3h
The time difference between Rancho-Cucamonga (America/Los_Angeles) and Norwalk (America/New_York) is 3 hours. This means that it is now 02:39 (24.09.2019) in Rancho-Cucamonga and 05:39 (24.09.2019) in Norwalk.
To calculate the distance between Rancho-Cucamonga and Norwalk, the place names are converted into coordinates (latitude and longitude). The respective geographic centre is used for cities, regions and countries. To calculate the distance the Haversine formula is applied.
Norwalk is just as far away from Rancho-Cucamonga as Rancho-Cucamonga from New York (3,880 km), Brooklyn (3,885 km), Queens (3,894 km), Montreal (3,913 km), Philadelphia (3,787 km), Manhattan (3,883 km), The Bronx (3,891 km), Managua (4,002 km), Tegucigalpa (3,780 km), Ottawa (3,748 km).
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