Distance from Chinnasekkadu to Jacksonville
Driving route: -- ( - )
Driving route: -- ( - )
Extended route information
The flight distance between the nearest airports Chinnasekkadu (MAA) and Jacksonville (JAX) is 9,199.33 mi (14,804.90 km). This corresponds to an approximate flight time of 17h 55min. Similar flight routes: MAA → DAB , MAA → SFB , MAA → SAV , MAA → MCO , BLR → JAX
Bearing: 276.55° (W)The initial bearing on the course from Chinnasekkadu to Jacksonville is 276.55° and the compass direction is W.
Midpoint: 67.15324,20.02641The geographic midpoint between Chinnasekkadu and Jacksonville is in 4,599.94 mi (7,402.89 km) distance between both points in a bearing of 276.55°. It is located in Sweden, Norrbottens län (Sverige, Norrbottens län).
Distance: 9,199.88 mi (14,805.77 km)The shortest distance (air line) between Chinnasekkadu and Jacksonville is 9,199.88 mi (14,805.77 km).
Driving route: -- ( - )The shortest route between Chinnasekkadu and Jacksonville is according to the route planner. The driving time is approx. . Half of the trip is reached in .
Time difference: -9.5hThe time difference between Chinnasekkadu (Asia/Kolkata) and Jacksonville (America/New_York) is -9.5 hours. This means that it is now 11:25 (28.04.2024) in Chinnasekkadu and 01:55 (28.04.2024) in Jacksonville.
How is the distance calculated?
To calculate the distance between Chinnasekkadu and Jacksonville, the place names are converted into coordinates (latitude and longitude). The respective geographic centre is used for cities, regions and countries. To calculate the distance the Haversine formula is applied.
Similar routes:
Similar distance (± 0.5%)
Jacksonville is just as far away from Chinnasekkadu as Chinnasekkadu from Buenos Aires (15,228 km), São Paulo (14,324 km), Los Angeles (14,412 km), Caracas (15,535 km), Houston (15,219 km), Brasília (14,442 km), Santo Domingo (15,211 km), Curitiba (14,579 km), Manaus (15,510 km), Phoenix (14,670 km).
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