Distance from Johannesburg to Alexandria
Driving route: -- ( - )
Driving route: -- ( - )
Extended route information
The flight distance between the nearest airports Johannesburg (JNB) and Alexandria (DCA) is 8,102.33 mi (13,039.44 km). This corresponds to an approximate flight time of 15h 50min. Similar flight routes: JNB → IAD , JNB → BWI , JNB → RIC , JNB → PHF , GBE → DCABearing: 303.41° (WNW)
The initial bearing on the course from Johannesburg to Alexandria is 303.41° and the compass direction is WNW.Midpoint: 10.25016,-19.25287
The geographic midpoint between Johannesburg and Alexandria is in 4,052.55 mi (6,521.95 km) distance between both points in a bearing of 303.41°.Distance: 8,105.11 mi (13,043.91 km)
The shortest distance (air line) between Johannesburg and Alexandria is 8,105.11 mi (13,043.91 km).Driving route: -- ( - )
The shortest route between Johannesburg and Alexandria is according to the route planner. The driving time is approx. . Half of the trip is reached in .Time difference: -7h
The time difference between Johannesburg (Africa/Johannesburg) and Alexandria (America/New_York) is -7 hours. This means that it is now 23:50 (06.12.2023) in Johannesburg and 16:50 (06.12.2023) in Alexandria.
How is the distance calculated?
To calculate the distance between Johannesburg and Alexandria, the place names are converted into coordinates (latitude and longitude). The respective geographic centre is used for cities, regions and countries. To calculate the distance the Haversine formula is applied.
Similar distance (± 0.5%)
Alexandria is just as far away from Johannesburg as Johannesburg from Seoul (12,488 km), Tokyo (13,539 km), New York City (12,839 km), Harbin (12,699 km), Changchun (12,546 km), Busan (12,586 km), Yokohama (13,530 km), Pyongyang (12,433 km), Incheon (12,462 km), Toronto (13,341 km).
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