Distance from Ranong to Jacksonville
Driving route: -- ( - )
Driving route: -- ( - )
Extended route information
The flight distance between the nearest airports Ranong (BKK) and Jacksonville (JAX) is 9,443.93 mi (15,198.54 km). This corresponds to an approximate flight time of 18h 22min. Similar flight routes: BKK → DAB , BKK → SFB , BKK → SAV , BKK → MCO , DMK → JAX
Bearing: 83.90° (E)The initial bearing on the course from Ranong to Jacksonville is 83.90° and the compass direction is E.
Midpoint: 80.44729,123.77881The geographic midpoint between Ranong and Jacksonville is in 4,723.73 mi (7,602.11 km) distance between both points in a bearing of 83.90°.
Distance: 9,447.46 mi (15,204.22 km)The shortest distance (air line) between Ranong and Jacksonville is 9,447.46 mi (15,204.22 km).
Driving route: -- ( - )The shortest route between Ranong and Jacksonville is according to the route planner. The driving time is approx. . Half of the trip is reached in .
Time difference: -11hThe time difference between Ranong (Asia/Jakarta) and Jacksonville (America/New_York) is -11 hours. This means that it is now 08:31 (28.04.2024) in Ranong and 21:31 (27.04.2024) in Jacksonville.
How is the distance calculated?
To calculate the distance between Ranong and Jacksonville, the place names are converted into coordinates (latitude and longitude). The respective geographic centre is used for cities, regions and countries. To calculate the distance the Haversine formula is applied.
Similar routes:
Similar distance (± 0.5%)
Jacksonville is just as far away from Ranong as Ranong from Mexico City (15,780 km), Salvador (15,678 km), Fortaleza (15,503 km), Houston (14,948 km), Iztapalapa (15,790 km), Ecatepec de Morelos (15,767 km), Guadalajara (15,407 km), Recife (15,214 km), San Antonio (14,853 km), Puebla (15,869 km).
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