The flight distance between the nearest airports San-Jose (SJC) and Jacksonville (CRG) is 2,351.62 mi (3,784.56 km). This corresponds to an approximate flight time of 4h 57min. Similar flight routes: SJC → CRG , SJC → JAX , SJC → CRG , SJC → CRG , SJC → JAXBearing: 89.81° (E)
The initial bearing on the course from San-Jose to Jacksonville is 89.81° and the compass direction is E.Midpoint: 35.52044,-100.9139
The geographic midpoint between San-Jose and Jacksonville is in 1,171.05 mi (1,884.63 km) distance between both points in a bearing of 89.81°. It is located in United States of America, Texas, Gray County.Distance: 2,342.10 mi (3,769.25 km)
The shortest distance (air line) between San-Jose and Jacksonville is 2,342.10 mi (3,769.25 km).Driving route: -- ( - )
The shortest route between San-Jose and Jacksonville is according to the route planner. The driving time is approx. . Half of the trip is reached in .Time difference: 3h
The time difference between San-Jose (America/Los_Angeles) and Jacksonville (America/New_York) is 3 hours. This means that it is now 20:28 (14.10.2019) in San-Jose and 23:28 (14.10.2019) in Jacksonville.
To calculate the distance between San-Jose and Jacksonville, the place names are converted into coordinates (latitude and longitude). The respective geographic centre is used for cities, regions and countries. To calculate the distance the Haversine formula is applied.
Jacksonville is just as far away from San-Jose as San-Jose from Toronto (3,620 km), Charlotte (3,659 km), Ottawa (3,903 km), Mérida (3,599 km), Mississauga (3,601 km), North York (3,619 km), Baltimore (3,916 km), Washington D.C. (3,890 km), Scarborough (3,632 km).
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