Distance from Santiago-Papasquiaro to Alexandria
Driving route: -- ( - )
Driving route: -- ( - )
Extended route information
The flight distance between the nearest airports Santiago-Papasquiaro (PVR) and Alexandria (DCA) is 1,912.57 mi (3,077.99 km). This corresponds to an approximate flight time of 4h 7min. Similar flight routes: PVR → IAD , PVR → BWI , PVR → RIC , PVR → PHF , SJD → DCA
Bearing: 59.72° (ENE)The initial bearing on the course from Santiago-Papasquiaro to Alexandria is 59.72° and the compass direction is ENE.
Midpoint: 32.60841,-92.29001The geographic midpoint between Santiago-Papasquiaro and Alexandria is in 954.67 mi (1,536.39 km) distance between both points in a bearing of 59.72°. It is located in United States of America, Louisiana, Union Parish.
Distance: 1,909.34 mi (3,072.78 km)The shortest distance (air line) between Santiago-Papasquiaro and Alexandria is 1,909.34 mi (3,072.78 km).
Driving route: -- ( - )The shortest route between Santiago-Papasquiaro and Alexandria is according to the route planner. The driving time is approx. . Half of the trip is reached in .
Time difference: 2hThe time difference between Santiago-Papasquiaro (America/Monterrey) and Alexandria (America/New_York) is 2 hours. This means that it is now 05:30 (10.05.2024) in Santiago-Papasquiaro and 07:30 (10.05.2024) in Alexandria.
How is the distance calculated?
To calculate the distance between Santiago-Papasquiaro and Alexandria, the place names are converted into coordinates (latitude and longitude). The respective geographic centre is used for cities, regions and countries. To calculate the distance the Haversine formula is applied.
Similar routes:
Similar distance (± 0.5%)
Alexandria is just as far away from Santiago-Papasquiaro as Santiago-Papasquiaro from Toronto (3,150 km), Calgary (3,010 km), Kingston (3,044 km), Seattle (2,941 km), Mississauga (3,126 km), Baltimore (3,128 km), Washington (3,077 km), Vancouver (3,123 km), New Kingston (3,045 km), Santiago de Cuba (3,074 km).
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